L^2-7L-260=0

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Solution for L^2-7L-260=0 equation:


Simplifying
L2 + -7L + -260 = 0

Reorder the terms:
-260 + -7L + L2 = 0

Solving
-260 + -7L + L2 = 0

Solving for variable 'L'.

Factor a trinomial.
(-13 + -1L)(20 + -1L) = 0

Subproblem 1

Set the factor '(-13 + -1L)' equal to zero and attempt to solve: Simplifying -13 + -1L = 0 Solving -13 + -1L = 0 Move all terms containing L to the left, all other terms to the right. Add '13' to each side of the equation. -13 + 13 + -1L = 0 + 13 Combine like terms: -13 + 13 = 0 0 + -1L = 0 + 13 -1L = 0 + 13 Combine like terms: 0 + 13 = 13 -1L = 13 Divide each side by '-1'. L = -13 Simplifying L = -13

Subproblem 2

Set the factor '(20 + -1L)' equal to zero and attempt to solve: Simplifying 20 + -1L = 0 Solving 20 + -1L = 0 Move all terms containing L to the left, all other terms to the right. Add '-20' to each side of the equation. 20 + -20 + -1L = 0 + -20 Combine like terms: 20 + -20 = 0 0 + -1L = 0 + -20 -1L = 0 + -20 Combine like terms: 0 + -20 = -20 -1L = -20 Divide each side by '-1'. L = 20 Simplifying L = 20

Solution

L = {-13, 20}

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